
2019 18

Lecture1.1

Lecture1.2

Lecture1.3

Lecture1.4

Lecture1.5

Lecture1.6

Lecture1.7

Lecture1.8

Lecture1.9

Lecture1.10

Lecture1.11

Lecture1.12

Lecture1.13

Lecture1.14

Lecture1.15

Lecture1.16

Lecture1.17

Lecture1.18


MATHEMATICS 29

Lecture2.1

Lecture2.2

Lecture2.3

Lecture2.4

Lecture2.5

Lecture2.6

Lecture2.7

Lecture2.8

Lecture2.9

Lecture2.10

Lecture2.11

Lecture2.12

Lecture2.13

Lecture2.14

Lecture2.15

Lecture2.16

Lecture2.17

Lecture2.18

Lecture2.19

Lecture2.20

Lecture2.21

Lecture2.22

Lecture2.23

Lecture2.24

Lecture2.25

Lecture2.26

Lecture2.27

Lecture2.28

Lecture2.29


ENGLISH LANGUAGE 29

Lecture3.1

Lecture3.2

Lecture3.3

Lecture3.4

Lecture3.5

Lecture3.6

Lecture3.7

Lecture3.8

Lecture3.9

Lecture3.10

Lecture3.11

Lecture3.12

Lecture3.13

Lecture3.14

Lecture3.15

Lecture3.16

Lecture3.17

Lecture3.18

Lecture3.19

Lecture3.20

Lecture3.21

Lecture3.22

Lecture3.23

Lecture3.24

Lecture3.25

Lecture3.26

Lecture3.27

Lecture3.28

Lecture3.29


INTEGRATED SCIENCE 29

Lecture4.1

Lecture4.2

Lecture4.3

Lecture4.4

Lecture4.5

Lecture4.6

Lecture4.7

Lecture4.8

Lecture4.9

Lecture4.10

Lecture4.11

Lecture4.12

Lecture4.13

Lecture4.14

Lecture4.15

Lecture4.16

Lecture4.17

Lecture4.18

Lecture4.19

Lecture4.20

Lecture4.21

Lecture4.22

Lecture4.23

Lecture4.24

Lecture4.25

Lecture4.26

Lecture4.27

Lecture4.28

Lecture4.29


SOCIAL STUDIES 29

Lecture5.1

Lecture5.2

Lecture5.3

Lecture5.4

Lecture5.5

Lecture5.6

Lecture5.7

Lecture5.8

Lecture5.9

Lecture5.10

Lecture5.11

Lecture5.12

Lecture5.13

Lecture5.14

Lecture5.15

Lecture5.16

Lecture5.17

Lecture5.18

Lecture5.19

Lecture5.20

Lecture5.21

Lecture5.22

Lecture5.23

Lecture5.24

Lecture5.25

Lecture5.26

Lecture5.27

Lecture5.28

Lecture5.29


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Bece Past Questions & Answers – 2017 (Maths)
2017 BECE Mathematics (Maths) Past Questions Paper One
1. If Q = {1, 3, 5, 7, 9, 10, 11, 13, 15} and T = {1, 2, 3, 5, 6, 7, 10, 11, 12}, find Q ∪ T
A. {1, 2, 3, 5, 7, 10, 11}
B. {1, 3, 5, 7, 9, 11, 13, 15}
C. {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13}
D. {1, 2, 3, 5, 6, 7, 9, 10, 11, 12, 13, 15}
D. {1, 2, 3, 5, 6, 7, 9, 10, 11, 12, 13, 15}
2. If 21 : 2x = 7 : 12, find the value of x.
A. 10
B. 12
C. 15
D. 18
D. 18
3. Given that , find the value of p.
A. 4
B. 3
C. 2
D. 1
A. 4
4. Simplify
A.
B.
C.
D.
C.
5. If A = {2, 6, 8} and B = {4, 6, 8, 10}, which of the following statements is true?
A. A ⊂ B
B. A ∩ B = {2, 6, 8}
C. A ∪ B = {2, 4, 6, 8, 10}
D. A ⊃ B
C. A ∪ B = {2, 4, 6, 8, 10}
6. Find the product of and
A.
B.
C.
D.
B.
7. The sum of the interior angles of a regular polygon with 10 sides is
A. 144°
B. 900°
C. 1440°
D. 1800°
7. C. 1440°
8. Solve
A.
B.
C
D.
B.
9. The ages of the members of a social club are 20 years, 55 years, 60 years and 25 years. Find the mean age of the members of the club.
A. 20 years
B. 30 years
C. 40 years
D. 50 years
9. C. 40 years
10. Evelyn saved GHc 35.48 every month for 8 months. How much did she save?
A. GHc 183.60
B. GHc 280.63
C. GHc 283.20
D. GHc 283.84
10. D. GHc 283.84
11. Evaluate:
A. 0.012
B. 0.12
C. 1.2
D. 12.0
11. B. 0.12
12. A woman deposited an amount of GHc 50,000.00 at a bank for 2 years at a rate of 20% per annum. Find the simple interest.
A. GHc 1,000.00
B. GHc 2,000.00
C. GHc 10,000.00
D. GHc 20,000.00
12. D. GHc 20,000.00
13. What is the total cost of x shirts at GHc 5.00 each and y shirts at GHc 1.50 each?
A. 5x + 1.5y
B. 5y + 1.5x
C. 5(x + 1.5y)
D. 1.5(5x + y)
13. A. 5x + 1.5y
14. At a meeting attended by 23 people, the females were 7 more than the males. How many males were there?
A. 8
B. 15
C. 16
D. 30
14. A. 8
15. Find the value of x in the diagram.
A. 28°
B. 30°
C. 34°
D. 60°
15. C. 34°
16. How many lines of symmetry does a rhombus have?
A. 2
B. 3
C. 4
D. 5
16. A. 2
17. In 1995, 215 boys and 185 girls were admitted into a Senior Secondary School. Find, correct to the nearest whole number, the percentage of girls admitted.
A. 46%
B. 47%
C. 53%
D. 54%
17. A. 46%
18. Simplify:
A.
B.
C
D.
D.
19. Solve 25x + 450 ≤ 3000
A. x ≥ 102
B. x ≤ 102
C. x ≥ 138
D. x ≤ 138
19. B. x ≤ 102
20. Given that a = and b = , find a + b.
A.
B.
C
D.
A.
21. Mr. Agyekum has 11 of the GHc 20.00 notes, 15 of the GHc 10.00 notes and 6 of the GHc 5.00 notes. How much does Mr. Agyekum have altogether?
A. 280.00
B. 320.00
C. 360.00
D. 400.00
21. D. GHc 400.00
22. A man travelled a distance of 1.5 km in 30 minutes. What distance can he cover in 50 minutes, travelling at the same speed?
A. 2.2 km
B. 2.5 km
C. 2.8 km
D. 3.2 km
22. B. 2.5 km
23.
In the diagram, UVW is an isosceles triangle, UV = UW and angle VUW = 70°. Find angle UVW
A. 70°
B. 60°
C. 55°
D. 35°
23. C. 55°
24. Arrange the following in descending order:
A.
B.
C.
D.
A.
25. The point D(4, 3) is reflected in the yaxis. Find the coordinates of its image.
A. (–4, –3)
B. (–3, 4)
C. (–4, 3)
D. (3, –4)
25. C. (–4, 3)
26. Simplify:
A.
B.
C
D.
A.
27. Divide 64.5 by 0.015, leaving the answer in standard form.
A.
B.
C
D.
B.
28. The point Q(–2, 3) is rotated anticlockwise about the origin through an angle of 90°. Find the coordinates of its image.
A. (–3, –2)
B. (–3, 2)
C. (3, –2)
D. (3, 2)
28. A. (–3, –2)
29. Elias bought five books. Their mean price was GHc 3.25. The total cost for four of the books was GHc 11.75. What was the cost of the fifth book?
A. GHc 3.50
B. GHc 4.00
C. GHc 4.20
D. GHc 4.50
29. D. GHc 4.50
Tins of milk each of volume 77 cm3 and weight 170 g were packed into an empty carton of volume 1540 cm3 and weight 500 g.
Use this information to answer Questions 30 and 31
30. How many tins of milk can be packed to fill the carton?
A. 2
B. 3
C. 20
D. 22
30. C. 20
31. What is the weight of the carton when packed with the tins of milk?
A. 2.06 kg
B. 2.94 kg
C. 3.90 kg
D. 8.50 kg
31. C. 3.90 kg
32. A piece of cloth is 8.4 m long. If 30 cm is needed to sew a napkin, how many napkins can be sewn from this piece of cloth?
A. 20
B. 25
C. 28
D. 30
32. C. 28
33. Express as a decimal fraction.
A. 0.3200
B. 0.3125
C. 0.3676
D. 0.3222
33. B. 0.3125
34. A match box contains 40 sticks. If 15 of them are spoil, find the probability that a stick chosen at random is not spoilt?
A.
B.
C.
D.
C.
The number of pupils who attended hospital from eight classes on a particular day are: 1, 5, 3, 1, 7, 5, 1, 1.
Use the information to answer Questions 35 to 37.
35. Find the median number.
A. 1
B. 2
C. 3
D. 4
35. B. 2
36. What is the modal number?
A. 1
B. 4
C. 5
D. 7
36. A. 1
37. Calculate the mean.
A. 2
B. 3
C. 4
D. 5
37. B. 3
38. The distance from the centre of a circle to any point on it is called
A. Circumference
B. Diameter
C. Radius
D. Sector
38. C. Radius
39. Express 1352 as a product of prime factors.
A.
B.
C
D.
B.
40. Which of the following statements about sets is true?
A. Every set is a subset of the null set.
B. The universal set is the subset of the null set
C. The intersection of two sets is always a null set
D. The universal set is the union of all its subsets.
40. D. The universal set is the union of all its subsets
2017 BECE Mathematics (Maths) Past Questions Paper TWO
1. (a) In a class of 30 girls, 17 play football, 12 play hockey and 4 play both games.
Draw a Venn diagram to illustrate the given information
How many girls play:
(α) one or two of the games;
(β) none of the two games?
(b)
In the diagram, ABCD is a circle of radius 14 cm and centre O. Line BO is perpendicular to line AC. Calculate, the total area of the shaded portions.
[Take π = 22/7]
1. (a) In a class of 30 girls, 17 play football, 12 play hockey and 4 play both games.
Draw a Venn diagram to illustrate the given information
Let
U = Total number in class
F = Number of girls who play football
H = Number of girls who play hockey
n = Number of girls who play none of the two games
How many girls play:
(α) one or two of the games;
= 13 + 4 + 8
= 25
(β) none of the two games?
= 30 – 25
= 5
(b)
Total area of shaded portion
= Area of semicircle – Area of the triangle ABC
Area of semicircle =
= ×22/7×14×14
= 11×2×14
=
Area of triangle ABC = b h
= ×AC× OB
= ×28×14
= 14×14
=
Therefore, Area of shaded portion = 308 – 196
=
2. (a) Two consecutive odd numbers are such that seven times the smaller, subtracted from nine times the bigger, gives 144. Find the two numbers.
(b) A paint manufacturing company has a machine which fills 24 tins with paint in 5 minutes.
(i) How many tins will the machine fill in
(α) 1 minute, correct to the nearest whole number?
(β) 1 hour?
(ii) How many hours will it take to fill 1440 tins?
(c) Given that ,a=3,d=4 and n=10, find the value of s.
a. Let the first (smaller) odd number = n
Then the next (bigger) odd number = n + 2
Seven times the smaller = 7n
Nine times the bigger = 9 (n + 2)
Hence ⇒ 9(n+2)7n=144
⇒ 9n+187n=144
⇒ 9n7n = 14418
⇒ 2n = 126
⇒ n =
⇒ n = 63
Therefore the smaller odd number is 63
And the bigger odd number = 63 +2 = 65
(b) A paint manufacturing company has a machine which fills 24 tins with paint in 5 minutes.
(i) How many tins will the machine fill in
(α) 1 minute, correct to the nearest whole number?
If 5 minutes → 24 tins,
then 1 minute → = tins ≈ 5 tins
Hence, 1 minute → 5 tins (to the nearest whole number)
(β) 1 hour?
If 1 minute →
then 1 hour (60 minutes) → ×60
= 24 × 12
= 288 tins
(ii) How many hours will it take to fill 1440 tins?
If 288 tins → 1 hour
then 1440 tins → ×1 hour
= 5 hours
(c) Given that s=n/2 [2a+(n1)d],a=3,d=4 and n=10, find the value of s.
⇒ s=[2×3+(101)4],
⇒ s=5 [6+(9)4],
⇒ s=5 [6+36],
⇒ s = 5(42)
⇒ s = 210
3. (a) Using a ruler and pair of compasses only, construct:
(i) a triangle ABC, with BC = 9cm, AC = 8 and AB = 6 cm;
(ii) the perpendicular bisector of line BC;
(iii) the bisector of angle ACB
(b) Label the point of intersection of the two bisectors as Y.
(c) Draw a line to join B and Y.
(d) Measure
(i) BY;
(ii) YC;
(iii) the base angles of triangle BYC.
(e) What type of triangle is BYC?
3. a. Using a rulaer and pair of compasses only, construct;
(i) a triangle ABC, with BC = 9cm, AC=8cm and AB =6cm;
(ii) the perpendicular bisector of line BC;
(iii) the bisector of angle ACB
(b) Label the point of intersection of the two bisectors as Y.
See diagram (point Y within triangle ABC)
(c) Draw a line to join B and Y.
See diagram (blue line from B to Y)
(d) Measure
(i) BY;
= 4.8 cm [± 0.1 cm]
(ii) YC;
= 4.8 cm [± 0.1 cm]
(iii) the base angles of triangle BYC.
= 20.5° [or 20° or 21°]
(e) What type of triangle is BYC?
= Isosceles triangle
4. (a) The table below shows the ages of students admitted in a hospital.
Age (years)  10  11  12  13  14  15 
Number of Students  5  1  7  10  3  4 
Use the information to answer the following questions:
(i) What is the modal age?
(ii) Calculate, correct to two decimal places, the mean age of the students.
(b) Rice is sold at GHc 56.00 per bag of 50 kg. A trader bought some bags of rice and paid GHc 1,344.00.
(i) How many bags of rice did the trader buy?
(ii) If the trader retailed the bags of rice at GHc 1.40 per kg, how much profit was made on 1 kg of rice?
4. (a) The table below shows the ages of students admitted in a hospital.
Age (years)  10  11  12  13  14  15 
Number of Students  5  1  7  10  3  4 
Use the information to answer the following questions:
(i) What is the modal age?
= 13 years (the age with the highest no. of students)
(ii) Calculate, correct to two decimal places, the mean age of the students.
Mean age =
=
= \frac{ 377 }{30}
=
= 12.57 years.
(a) (ii) ALTERNATIVE APPROACH (using the table)
Mean age =
=
=
= 12.57 years
b.
(b) Rice is sold at GHc 56.00 per bag of 50 kg. A trader bought some bags of rice and paid GHc 1,344.00.
(i) How many bags of rice did the trader buy?
No. of bags bought =
= 24 bags
(ii) If the trader retailed the bags of rice at GHc 1.40 per kg, how much profit was made on 1 kg of rice?
Profit = Selling Price – Cost Price
Cost Price of 1 kg =
= GHc 1.12
Selling Price of 1 kg = GHc 1.40
Therefore Profit made on 1 kg = 1.40 – 1.12
= GHc 0.28
(b) (ii) ALTERNATIVE APPROACH (using the totals)
Total amount of rice = 24 × 50 kg
= 1200 kg
Total Retailed (selling) price = GHc 1.40 × 1200
= GHc 1680
Total cost price (given) = GHc 1344
Profit on total amount = Total SP – Total CP
= 1680 – 1344
= GHc 336
Profit on each kg (1 kg) =
= GHc 0.28
5. (a) Using a scale of 2 cm to 1 unit on both axes, draw on a graph sheet two perpendicular axes Ox and Oy for 5≤x≤5 and 5≤y≤5
(i) Plot, indicating the coordinates of all points A(2, 3) and B(–3, 4). Draw a straight line passing through the points A and B.
(ii) Plot on the same graph sheet, indicating the coordinates of the points C(4, 2) and D(–2, –3). Draw a straight line passing through the points to meet line AB
(b) Using the graphs in 5(a),
(i) find the values of y when x = –2;
(ii) measure the angle between the lines AB and CD.
*Make sure you follow the instructions in order
(a) Using a scale of 2 cm to 1 unit on both axes, draw on a graph sheet two perpendicular axes Ox and Oy for 5≤x≤5 and 5≤y≤5
(i) Plot, indicating the coordinates of all points A(2, 3) and B(–3, 4). Draw a straight line passing through the points A and B.
(ii) Plot on the same graph sheet, indicating the coordinates of the points C(4, 2) and D(–2, –3). Draw a straight line passing through the points to meet line AB
(b) Using the graphs in 5(a),
(i) find the values of y when x = –2;
Values of y = –3 and 3.8 [± 0.1]
(ii) measure the angle between the lines AB and CD.
Acute angle between lines = 51° [± 0.1]
OR
Obtuse angle between lines = 129° [± 0.1]
6. (a)If ,
and , find the:
(i) values of x and y
(ii) components of m
(b) (i) Solve the inequality:
(ii) Illustrate the answer in b(i) on a number line.
(c)
In the diagram, AB is parallel to CD. Find the value of:
(i) x
(ii) y
If ,
and , find the:
Since
Then from the horizontal (x) component,
⇒ 2x+1+6=9
⇒ 2x=916
⇒ 2x=2
⇒ x=1
and from the vertical (y) component,
⇒ 23y8=12
⇒ 28+12=3y
⇒ 6=3y
⇒
⇒ 2=y
⇒ y= 2
ii) components of m
m =
=
=
=
(b) (i) Solve the inequality:
⇒
⇒ 3(x+1)+4≤2(x2)+20
⇒
⇒
⇒
⇒ x\leq9
c.
In the diagram above , AB is parallel to CD. Find the value of:
(i) x
Angle x and (47° + 102°) form vertically opposite angles
Hence, x=47°+102°
⇒ x=149°
(ii) y
x is congruent to the angles adjacent to y (alternate or corresponding)
Hence y+149°=180°
⇒ y=180°149°
⇒ y=31°